TheCloud/panda3d
1
0
Fork 0
mirror of https://github.com/panda3d/panda3d.git synced 2025-10-04 10:54:24 -04:00
Code Issues Packages Projects Releases Wiki Activity

hacked in a doorway

Browse Source
This commit is contained in:
Darren Ranalli 2003-09-11 07:12:21 +00:00
parent 16166d6573
commit 3700376719
1 changed files with 7 additions and 2 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

9
direct/src/level/DistributedLevel.py
View File

@ -108,6 +108,11 @@ class DistributedLevel(DistributedObject.DistributedObject,
self.notify.debug('zones: %s' % self.zoneNums) self.notify.debug('zones: %s' % self.zoneNums)
assert sameElements(self.zoneNums, self.spec['zones'].keys() + [0]) assert sameElements(self.zoneNums, self.spec['zones'].keys() + [0])
# hack in another doorway
dw = self.geom.attachNewNode('Doorway27')
dw.setPos(-49.4,86.7,19.26)
dw.setH(0)
# find the doorway nodes # find the doorway nodes
self.doorwayNum2Node = findNumberedNodes('Doorway') self.doorwayNum2Node = findNumberedNodes('Doorway')
@ -224,7 +229,7 @@ class DistributedLevel(DistributedObject.DistributedObject,
def enterZone(self, zoneNum): def enterZone(self, zoneNum):
if not DistributedLevel.WantVisibility: if not DistributedLevel.WantVisibility:
return return
if zoneNum == self.curZoneNum: if zoneNum == self.curZoneNum:
return return
@ -233,7 +238,7 @@ class DistributedLevel(DistributedObject.DistributedObject,
# use dicts to efficiently ensure that there are no duplicates # use dicts to efficiently ensure that there are no duplicates
visibleZoneNums = list2dict([zoneNum]) visibleZoneNums = list2dict([zoneNum])
visibleZoneNums.update(list2dict(zoneSpec['visibility'])) visibleZoneNums.update(list2dict(zoneSpec['visibility']))
if DistributedLevel.HideZones: if DistributedLevel.HideZones:
# figure out which zones are new and which are going invisible # figure out which zones are new and which are going invisible
# use dicts because it's faster to use dict.has_key(x) # use dicts because it's faster to use dict.has_key(x)