Bumping libc files for unsupported architectures, to simplify merging. A bunch of small fixes: * in libutil update * the macro in endian.h * some undefined types due to clear separation from host. * Fix a warning for cdbr.c Some modification which were required for the new build system: * inclusion path for const.h in sconst, still hacky * Removed default malloc.c which conflicts on some occasions.
		
			
				
	
	
		
			273 lines
		
	
	
		
			7.6 KiB
		
	
	
	
		
			Plaintext
		
	
	
	
	
	
			
		
		
	
	
			273 lines
		
	
	
		
			7.6 KiB
		
	
	
	
		
			Plaintext
		
	
	
	
	
	
/*
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 * Copyright (c) 1992, 1993
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 *	The Regents of the University of California.  All rights reserved.
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 *
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 * This software was developed by the Computer Systems Engineering group
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 * at Lawrence Berkeley Laboratory under DARPA contract BG 91-66 and
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 * contributed to Berkeley.
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 *
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 * Redistribution and use in source and binary forms, with or without
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 * modification, are permitted provided that the following conditions
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 * are met:
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 * 1. Redistributions of source code must retain the above copyright
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 *    notice, this list of conditions and the following disclaimer.
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 * 2. Redistributions in binary form must reproduce the above copyright
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 *    notice, this list of conditions and the following disclaimer in the
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 *    documentation and/or other materials provided with the distribution.
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 * 3. Neither the name of the University nor the names of its contributors
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 *    may be used to endorse or promote products derived from this software
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 *    without specific prior written permission.
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 *
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 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
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 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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 * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
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 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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 * SUCH DAMAGE.
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 *
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 * from: Header: divrem.m4,v 1.4 92/06/25 13:23:57 torek Exp
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 * $NetBSD: divrem.m4,v 1.6 2011/03/23 20:54:35 martin Exp $
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 */
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/*
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 * Division and remainder, from Appendix E of the Sparc Version 8
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 * Architecture Manual, with fixes from Gordon Irlam.
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 */
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#if defined(LIBC_SCCS) && !defined(lint)
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	.asciz "@(#)divrem.m4	8.1 (Berkeley) 6/4/93"
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#endif /* LIBC_SCCS and not lint */
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/*
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 * Input: dividend and divisor in %o0 and %o1 respectively.
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 *
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 * m4 parameters:
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 *  NAME	name of function to generate
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 *  OP		OP=div => %o0 / %o1; OP=rem => %o0 % %o1
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 *  S		S=true => signed; S=false => unsigned
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 *
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 * Algorithm parameters:
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 *  N		how many bits per iteration we try to get (4)
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 *  WORDSIZE	total number of bits (32)
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 *
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 * Derived constants:
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 *  TWOSUPN	2^N, for label generation (m4 exponentiation currently broken)
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 *  TOPBITS	number of bits in the top `decade' of a number
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 *
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 * Important variables:
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 *  Q		the partial quotient under development (initially 0)
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 *  R		the remainder so far, initially the dividend
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 *  ITER	number of main division loop iterations required;
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 *		equal to ceil(log2(quotient) / N).  Note that this
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 *		is the log base (2^N) of the quotient.
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 *  V		the current comparand, initially divisor*2^(ITER*N-1)
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 *
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 * Cost:
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 *  Current estimate for non-large dividend is
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 *	ceil(log2(quotient) / N) * (10 + 7N/2) + C
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 *  A large dividend is one greater than 2^(31-TOPBITS) and takes a
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 *  different path, as the upper bits of the quotient must be developed
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 *  one bit at a time.
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 */
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define(N, `4')
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define(TWOSUPN, `16')
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define(WORDSIZE, `32')
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define(TOPBITS, eval(WORDSIZE - N*((WORDSIZE-1)/N)))
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define(dividend, `%o0')
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define(divisor, `%o1')
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define(Q, `%o2')
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define(R, `%o3')
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define(ITER, `%o4')
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define(V, `%o5')
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/* m4 reminder: ifelse(a,b,c,d) => if a is b, then c, else d */
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define(T, `%g1')
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define(SC, `%g5')
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ifelse(S, `true', `define(SIGN, `%g6')')
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/*
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 * This is the recursive definition for developing quotient digits.
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 *
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 * Parameters:
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 *  $1	the current depth, 1 <= $1 <= N
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 *  $2	the current accumulation of quotient bits
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 *  N	max depth
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 *
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 * We add a new bit to $2 and either recurse or insert the bits in
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 * the quotient.  R, Q, and V are inputs and outputs as defined above;
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 * the condition codes are expected to reflect the input R, and are
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 * modified to reflect the output R.
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 */
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define(DEVELOP_QUOTIENT_BITS,
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`	! depth $1, accumulated bits $2
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	bl	L.$1.eval(TWOSUPN+$2)
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	srl	V,1,V
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	! remainder is positive
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	subcc	R,V,R
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	ifelse($1, N,
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	`	b	9f
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		add	Q, ($2*2+1), Q
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	', `	DEVELOP_QUOTIENT_BITS(incr($1), `eval(2*$2+1)')')
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L.$1.eval(TWOSUPN+$2):
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	! remainder is negative
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	addcc	R,V,R
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	ifelse($1, N,
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	`	b	9f
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		add	Q, ($2*2-1), Q
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	', `	DEVELOP_QUOTIENT_BITS(incr($1), `eval(2*$2-1)')')
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	ifelse($1, 1, `9:')')
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#include <machine/asm.h>
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#include <machine/trap.h>
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FUNC(NAME)
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ifelse(S, `true',
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`	! compute sign of result; if neither is negative, no problem
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	orcc	divisor, dividend, %g0	! either negative?
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	bge	2f			! no, go do the divide
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	ifelse(OP, `div',
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		`xor	divisor, dividend, SIGN',
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		`mov	dividend, SIGN')	! compute sign in any case
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	tst	divisor
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	bge	1f
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	tst	dividend
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	! divisor is definitely negative; dividend might also be negative
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	bge	2f			! if dividend not negative...
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	neg	divisor			! in any case, make divisor nonneg
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1:	! dividend is negative, divisor is nonnegative
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	neg	dividend		! make dividend nonnegative
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2:
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')
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	! Ready to divide.  Compute size of quotient; scale comparand.
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	orcc	divisor, %g0, V
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	bnz	1f
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	mov	dividend, R
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		! Divide by zero trap.  If it returns, return 0 (about as
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		! wrong as possible, but that is what SunOS does...).
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		t	ST_DIV0
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		retl
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		clr	%o0
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1:
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	cmp	R, V			! if divisor exceeds dividend, done
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	blu	Lgot_result		! (and algorithm fails otherwise)
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	clr	Q
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	sethi	%hi(1 << (WORDSIZE - TOPBITS - 1)), T
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	cmp	R, T
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	blu	Lnot_really_big
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	clr	ITER
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	! `Here the dividend is >= 2^(31-N) or so.  We must be careful here,
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	! as our usual N-at-a-shot divide step will cause overflow and havoc.
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	! The number of bits in the result here is N*ITER+SC, where SC <= N.
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	! Compute ITER in an unorthodox manner: know we need to shift V into
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	! the top decade: so do not even bother to compare to R.'
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	1:
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		cmp	V, T
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		bgeu	3f
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		mov	1, SC
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		sll	V, N, V
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		b	1b
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		inc	ITER
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	! Now compute SC.
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	2:	addcc	V, V, V
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		bcc	Lnot_too_big
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		inc	SC
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		! We get here if the divisor overflowed while shifting.
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		! This means that R has the high-order bit set.
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		! Restore V and subtract from R.
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		sll	T, TOPBITS, T	! high order bit
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		srl	V, 1, V		! rest of V
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		add	V, T, V
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		b	Ldo_single_div
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		dec	SC
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	Lnot_too_big:
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	3:	cmp	V, R
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		blu	2b
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		nop
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		be	Ldo_single_div
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		nop
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	/* NB: these are commented out in the V8-Sparc manual as well */
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	/* (I do not understand this) */
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	! V > R: went too far: back up 1 step
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	!	srl	V, 1, V
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	!	dec	SC
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	! do single-bit divide steps
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	!
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	! We have to be careful here.  We know that R >= V, so we can do the
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	! first divide step without thinking.  BUT, the others are conditional,
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	! and are only done if R >= 0.  Because both R and V may have the high-
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	! order bit set in the first step, just falling into the regular
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	! division loop will mess up the first time around.
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	! So we unroll slightly...
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	Ldo_single_div:
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		deccc	SC
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		bl	Lend_regular_divide
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		nop
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		sub	R, V, R
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		mov	1, Q
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		b	Lend_single_divloop
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		nop
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	Lsingle_divloop:
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		sll	Q, 1, Q
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		bl	1f
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		srl	V, 1, V
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		! R >= 0
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		sub	R, V, R
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		b	2f
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		inc	Q
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	1:	! R < 0
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		add	R, V, R
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		dec	Q
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	2:
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	Lend_single_divloop:
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		deccc	SC
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		bge	Lsingle_divloop
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		tst	R
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		b,a	Lend_regular_divide
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Lnot_really_big:
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1:
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	sll	V, N, V
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	cmp	V, R
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	bleu	1b
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	inccc	ITER
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	be	Lgot_result
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	dec	ITER
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	tst	R	! set up for initial iteration
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Ldivloop:
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	sll	Q, N, Q
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	DEVELOP_QUOTIENT_BITS(1, 0)
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Lend_regular_divide:
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	deccc	ITER
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	bge	Ldivloop
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	tst	R
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	bl,a	Lgot_result
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	! non-restoring fixup here (one instruction only!)
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ifelse(OP, `div',
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`	dec	Q
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', `	add	R, divisor, R
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')
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Lgot_result:
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ifelse(S, `true',
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`	! check to see if answer should be < 0
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	tst	SIGN
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	bl,a	1f
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	ifelse(OP, `div', `neg Q', `neg R')
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1:')
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	retl
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	ifelse(OP, `div', `mov Q, %o0', `mov R, %o0')
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