88 lines
		
	
	
		
			2.0 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			88 lines
		
	
	
		
			2.0 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /*	div64() - full 64-bit division		                           */
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| /*	rem64() - full 64-bit modulo		                           */
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| /*						Author: Erik van der Kouwe */
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| /*						              14 May 2010  */
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| #include <assert.h>
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| #include <minix/u64.h>
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| 
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| static u32_t shl64hi(u64_t i, unsigned shift)
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| {
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| 	/* compute the high-order 32-bit value in (i << shift) */
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| 	if (shift == 0)
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| 		return i.hi;
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| 	else if (shift < 32)
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| 		return (i.hi << shift) | (i.lo >> (32 - shift));
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| 	else if (shift == 32)
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| 		return i.lo;
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| 	else if (shift < 64)
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| 		return i.lo << (shift - 32);
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| 	else
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| 		return 0;		
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| }
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| 
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| static u64_t divrem64(u64_t *i, u64_t j)
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| {
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| 	u32_t i32, j32, q;
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| 	u64_t result = { 0, 0 };
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| 	unsigned shift;
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| 
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| 	assert(i);
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| 
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| 	/* this function is not suitable for small divisors */
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| 	assert(ex64hi(j) != 0);
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| 
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| 	/* as long as i >= j we work on reducing i */
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| 	while (cmp64(*i, j) >= 0) {
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| 		/* shift to obtain the 32 most significant bits */
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| 		shift = 63 - bsr64(*i);
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| 		i32 = shl64hi(*i, shift);
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| 		j32 = shl64hi(j, shift);
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| 
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| 		/* find a lower bound for *i/j */
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| 		if (j32 + 1 < j32) {
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| 			/* avoid overflow, since *i >= j we know q >= 1 */
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| 			q = 1; 
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| 		} else {
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| 			/* use 32-bit division, round j32 up to ensure that
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| 			 * we obtain a lower bound 
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| 			 */
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| 			q = i32 / (j32 + 1);
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| 
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| 			/* since *i >= j we know q >= 1 */
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| 			if (q < 1) q = 1;
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| 		}
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| 
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| 		/* perform the division using the lower bound we found */
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| 		*i = sub64(*i, mul64(j, cvu64(q)));
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| 		result = add64u(result, q);
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| 	}
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| 
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| 	/* if we get here then *i < j; because we round down we are finished */
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| 	return result;
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| }
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| 
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| u64_t div64(u64_t i, u64_t j)
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| {
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| 	/* divrem64 is unsuitable for small divisors, especially zero which would 
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| 	 * trigger a infinite loop; use assembly function in this case
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| 	 */
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| 	if (!ex64hi(j)) {
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| 		return div64u64(i, ex64lo(j));
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| 	}
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| 
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| 	return divrem64(&i, j);
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| }
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| 
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| u64_t rem64(u64_t i, u64_t j)
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| {
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| 	/* divrem64 is unsuitable for small divisors, especially zero which would 
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| 	 * trigger a infinite loop; use assembly function in this case
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| 	 */
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| 	if (!ex64hi(j)) {
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| 		return cvu64(rem64u(i, ex64lo(j)));
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| 	}
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| 
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| 	divrem64(&i, j);
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| 	return i;
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| }
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