 b6cbf7203b
			
		
	
	
		b6cbf7203b
		
	
	
	
	
		
			
			This patch imports the unmodified current version of NetBSD libc. The NetBSD includes are in /nbsd_include, while the libc code itself is split between lib/nbsd_libc and common/lib/libc.
		
			
				
	
	
		
			190 lines
		
	
	
		
			6.3 KiB
		
	
	
	
		
			ArmAsm
		
	
	
	
	
	
			
		
		
	
	
			190 lines
		
	
	
		
			6.3 KiB
		
	
	
	
		
			ArmAsm
		
	
	
	
	
	
| /*	$NetBSD: umul.S,v 1.1 2005/12/20 19:28:50 christos Exp $	*/
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| 
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| /*
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|  * Copyright (c) 1992, 1993
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|  *	The Regents of the University of California.  All rights reserved.
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|  *
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|  * This software was developed by the Computer Systems Engineering group
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|  * at Lawrence Berkeley Laboratory under DARPA contract BG 91-66 and
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|  * contributed to Berkeley.
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|  *
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|  * Redistribution and use in source and binary forms, with or without
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|  * modification, are permitted provided that the following conditions
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|  * are met:
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|  * 1. Redistributions of source code must retain the above copyright
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|  *    notice, this list of conditions and the following disclaimer.
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|  * 2. Redistributions in binary form must reproduce the above copyright
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|  *    notice, this list of conditions and the following disclaimer in the
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|  *    documentation and/or other materials provided with the distribution.
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|  * 3. Neither the name of the University nor the names of its contributors
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|  *    may be used to endorse or promote products derived from this software
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|  *    without specific prior written permission.
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|  *
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|  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
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|  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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|  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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|  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
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|  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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|  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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|  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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|  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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|  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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|  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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|  * SUCH DAMAGE.
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|  *
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|  * from: Header: umul.s,v 1.4 92/06/25 13:24:05 torek Exp
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|  */
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| 
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| #include <machine/asm.h>
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| #if defined(LIBC_SCCS) && !defined(lint)
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| #if 0
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| 	.asciz "@(#)umul.s	8.1 (Berkeley) 6/4/93"
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| #else
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| 	RCSID("$NetBSD: umul.S,v 1.1 2005/12/20 19:28:50 christos Exp $")
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| #endif
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| #endif /* LIBC_SCCS and not lint */
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| 
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| /*
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|  * Unsigned multiply.  Returns %o0 * %o1 in %o1%o0 (i.e., %o1 holds the
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|  * upper 32 bits of the 64-bit product).
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|  *
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|  * This code optimizes short (less than 13-bit) multiplies.  Short
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|  * multiplies require 25 instruction cycles, and long ones require
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|  * 45 instruction cycles.
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|  *
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|  * On return, overflow has occurred (%o1 is not zero) if and only if
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|  * the Z condition code is clear, allowing, e.g., the following:
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|  *
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|  *	call	.umul
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|  *	nop
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|  *	bnz	overflow	(or tnz)
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|  */
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| 
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| FUNC(.umul)
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| 	or	%o0, %o1, %o4
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| 	mov	%o0, %y		! multiplier -> Y
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| 	andncc	%o4, 0xfff, %g0	! test bits 12..31 of *both* args
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| 	be	Lmul_shortway	! if zero, can do it the short way
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| 	andcc	%g0, %g0, %o4	! zero the partial product and clear N and V
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| 
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| 	/*
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| 	 * Long multiply.  32 steps, followed by a final shift step.
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| 	 */
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| 	mulscc	%o4, %o1, %o4	! 1
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| 	mulscc	%o4, %o1, %o4	! 2
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| 	mulscc	%o4, %o1, %o4	! 3
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| 	mulscc	%o4, %o1, %o4	! 4
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| 	mulscc	%o4, %o1, %o4	! 5
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| 	mulscc	%o4, %o1, %o4	! 6
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| 	mulscc	%o4, %o1, %o4	! 7
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| 	mulscc	%o4, %o1, %o4	! 8
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| 	mulscc	%o4, %o1, %o4	! 9
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| 	mulscc	%o4, %o1, %o4	! 10
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| 	mulscc	%o4, %o1, %o4	! 11
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| 	mulscc	%o4, %o1, %o4	! 12
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| 	mulscc	%o4, %o1, %o4	! 13
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| 	mulscc	%o4, %o1, %o4	! 14
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| 	mulscc	%o4, %o1, %o4	! 15
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| 	mulscc	%o4, %o1, %o4	! 16
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| 	mulscc	%o4, %o1, %o4	! 17
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| 	mulscc	%o4, %o1, %o4	! 18
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| 	mulscc	%o4, %o1, %o4	! 19
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| 	mulscc	%o4, %o1, %o4	! 20
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| 	mulscc	%o4, %o1, %o4	! 21
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| 	mulscc	%o4, %o1, %o4	! 22
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| 	mulscc	%o4, %o1, %o4	! 23
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| 	mulscc	%o4, %o1, %o4	! 24
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| 	mulscc	%o4, %o1, %o4	! 25
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| 	mulscc	%o4, %o1, %o4	! 26
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| 	mulscc	%o4, %o1, %o4	! 27
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| 	mulscc	%o4, %o1, %o4	! 28
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| 	mulscc	%o4, %o1, %o4	! 29
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| 	mulscc	%o4, %o1, %o4	! 30
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| 	mulscc	%o4, %o1, %o4	! 31
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| 	mulscc	%o4, %o1, %o4	! 32
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| 	mulscc	%o4, %g0, %o4	! final shift
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| 
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| 
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| 	/*
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| 	 * Normally, with the shift-and-add approach, if both numbers are
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| 	 * positive you get the correct result.  WIth 32-bit two's-complement
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| 	 * numbers, -x is represented as
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| 	 *
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| 	 *		  x		    32
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| 	 *	( 2  -  ------ ) mod 2  *  2
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| 	 *		   32
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| 	 *		  2
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| 	 *
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| 	 * (the `mod 2' subtracts 1 from 1.bbbb).  To avoid lots of 2^32s,
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| 	 * we can treat this as if the radix point were just to the left
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| 	 * of the sign bit (multiply by 2^32), and get
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| 	 *
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| 	 *	-x  =  (2 - x) mod 2
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| 	 *
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| 	 * Then, ignoring the `mod 2's for convenience:
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| 	 *
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| 	 *   x *  y	= xy
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| 	 *  -x *  y	= 2y - xy
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| 	 *   x * -y	= 2x - xy
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| 	 *  -x * -y	= 4 - 2x - 2y + xy
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| 	 *
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| 	 * For signed multiplies, we subtract (x << 32) from the partial
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| 	 * product to fix this problem for negative multipliers (see mul.s).
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| 	 * Because of the way the shift into the partial product is calculated
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| 	 * (N xor V), this term is automatically removed for the multiplicand,
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| 	 * so we don't have to adjust.
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| 	 *
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| 	 * But for unsigned multiplies, the high order bit wasn't a sign bit,
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| 	 * and the correction is wrong.  So for unsigned multiplies where the
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| 	 * high order bit is one, we end up with xy - (y << 32).  To fix it
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| 	 * we add y << 32.
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| 	 */
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| 	tst	%o1
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| 	bl,a	1f		! if %o1 < 0 (high order bit = 1),
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| 	add	%o4, %o0, %o4	! %o4 += %o0 (add y to upper half)
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| 1:	rd	%y, %o0		! get lower half of product
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| 	retl
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| 	addcc	%o4, %g0, %o1	! put upper half in place and set Z for %o1==0
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| 
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| Lmul_shortway:
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| 	/*
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| 	 * Short multiply.  12 steps, followed by a final shift step.
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| 	 * The resulting bits are off by 12 and (32-12) = 20 bit positions,
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| 	 * but there is no problem with %o0 being negative (unlike above),
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| 	 * and overflow is impossible (the answer is at most 24 bits long).
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| 	 */
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| 	mulscc	%o4, %o1, %o4	! 1
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| 	mulscc	%o4, %o1, %o4	! 2
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| 	mulscc	%o4, %o1, %o4	! 3
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| 	mulscc	%o4, %o1, %o4	! 4
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| 	mulscc	%o4, %o1, %o4	! 5
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| 	mulscc	%o4, %o1, %o4	! 6
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| 	mulscc	%o4, %o1, %o4	! 7
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| 	mulscc	%o4, %o1, %o4	! 8
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| 	mulscc	%o4, %o1, %o4	! 9
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| 	mulscc	%o4, %o1, %o4	! 10
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| 	mulscc	%o4, %o1, %o4	! 11
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| 	mulscc	%o4, %o1, %o4	! 12
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| 	mulscc	%o4, %g0, %o4	! final shift
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| 
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| 	/*
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| 	 * %o4 has 20 of the bits that should be in the result; %y has
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| 	 * the bottom 12 (as %y's top 12).  That is:
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| 	 *
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| 	 *	  %o4		    %y
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| 	 * +----------------+----------------+
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| 	 * | -12- |   -20-  | -12- |   -20-  |
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| 	 * +------(---------+------)---------+
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| 	 *	   -----result-----
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| 	 *
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| 	 * The 12 bits of %o4 left of the `result' area are all zero;
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| 	 * in fact, all top 20 bits of %o4 are zero.
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| 	 */
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| 
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| 	rd	%y, %o5
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| 	sll	%o4, 12, %o0	! shift middle bits left 12
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| 	srl	%o5, 20, %o5	! shift low bits right 20
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| 	or	%o5, %o0, %o0
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| 	retl
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| 	addcc	%g0, %g0, %o1	! %o1 = zero, and set Z
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